4.7x^2+9x=0

Solution for 4.7x^2+9x=0 equation:

4.7x^2+9x=0

a = 4.7; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·4.7·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*4.7}=\frac{-18}{9.4}
=-1+5.375/5.875
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*4.7}=\frac{0}{9.4}
=0
$